ZOJ 1049 I Think I Need a Houseboat

原题链接

题目大意：Fred想在Louisiana买一套房子，但是堤坝不牢固，每年都要被河水侵蚀50平方英里。题目给出他豪宅的坐标，要求他被迫移民搬迁的年份。

解法：也没什么好说的，先求出两点间的距离，即半径，然后算出面积，在除以每年塌方的面积，向上取整即可。

参考代码：

#include <stdio.h>
#include <math.h>
#define PI 3.14
int main(){
	int n=1,N,year;
	float X,Y,dist,area;
	scanf("%d",&N);
	while(n<=N){
		scanf("%f%f",&X,&Y);
		dist = X*X+Y*Y;
		dist = sqrt(dist);
		area = PI*dist*dist/2/50;
		year = ceil(area);
		printf("Property %d: This property will begin eroding in year %d.\n",n,year);
		n++;
	}
	printf("END OF OUTPUT.");
	return 0;
}

ZOJ 1049 I Think I Need a Houseboat,布布扣,bubuko.com

ZOJ 1049 I Think I Need a Houseboat

原文：http://www.cnblogs.com/naive/p/3568748.html