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LeetCode:Path Sum

时间:2014-11-17 10:46:42      阅读:229      评论:0      收藏:0      [点我收藏+]

题目描述:

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,
              5
             /             4   8
           /   /           11  13  4
         /  \              7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

代码:

bool Solution::hasPathSum(TreeNode *root, int sum)
{
    if(root == NULL)
        return false;
    if(root->left == NULL && root->right == NULL)
        return root->val - sum;
    else
        return hasPathSum(root->left,sum-root->val) || hasPathSum(root->right,sum-root->val);
}


LeetCode:Path Sum

原文:http://blog.csdn.net/yao_wust/article/details/41204391

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