a letter and a number

描述

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

输入

On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).

输出

for each case, you should the result of y+f(x) on a line

样例输入

6
R 1
P 2
G 3
r 1
p 2
g 3

样例输出

19
18
10
-17
-14
-4

 1 #include <stdio.h>
 2 #include <ctype.h>
 3 
 4 int main(){
 5     int T;
 6     char c;
 7     int n;
 8     int result;
 9     
10     scanf("%d",&T);
11     getchar();
12     
13     while(T--){
14         scanf("%c %d",&c,&n);
15         getchar();
16         
17         if(islower(c)){
18             result=-(c-‘a‘+1)+n;
19         }
20         
21         else
22             result=c-‘A‘+1+n;
23             
24         printf("%d\n",result);
25     }
26     return 0;
27 }

 

a letter and a number

原文：http://www.cnblogs.com/zqxLonely/p/4098557.html