| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 13321 | Accepted: 2930 |
Description
Input
Output
Sample Input
3 4 7 2 0 4 2 6 1 2 40 3 2 70 2 3 90 1 3 120
Sample Output
110
Hint
Source
//2436K 219MS
#include<stdio.h>
#include<string.h>
#include<algorithm>
#define inff 200000000007
#define inf 0x3f3f3f
#define M 1007
#define MIN(a,b) a>b?b:a;
using namespace std;
struct E
{
int v,w,next;
}edg[500000];
int dis[2000],gap[2000],head[2000],nodes;
int sourse,sink,nn;
int cow[M][2],n,s,t,countt;
long long g[M][M],maxx;
void init()
{
nodes=0;maxx=0,countt=0;
memset(head,-1,sizeof(head));
for(int i=1;i<=n;i++)
for(int j=1;j<=n;j++)
if(i==j)g[i][j]=0;
else g[i][j]=inff;
}
void floyd()
{
for(int k=1;k<=n;k++)
for(int i=1;i<=n;i++)
for(int j=1;j<=n;j++)
if(g[i][k]+g[k][j]<g[i][j])
g[i][j]=g[i][k]+g[k][j];
}
long long findmin()
{
long long maxxx=0;
for(int i=1;i<=n;i++)
for(int j=1;j<=n;j++)
if(i!=j&&g[i][j]!=inff)
maxxx=max(maxxx,g[i][j]);
return maxxx;
}
void addedge(int u,int v,int w)
{
edg[nodes].v=v;
edg[nodes].w=w;
edg[nodes].next=head[u];
head[u]=nodes++;
edg[nodes].v=u;
edg[nodes].w=0;
edg[nodes].next=head[v];
head[v]=nodes++;
}
int dfs(int src,int aug)
{
if(src==sink)return aug;
int left=aug,mindis=nn;
for(int j=head[src];j!=-1;j=edg[j].next)
{
int v=edg[j].v;
if(edg[j].w)
{
if(dis[v]+1==dis[src])
{
int minn=MIN(left,edg[j].w);
minn=dfs(v,minn);
edg[j].w-=minn;
edg[j^1].w+=minn;
left-=minn;
if(dis[sourse]>=nn)return aug-left;
if(left==0)break;
}
if(dis[v]<mindis)
mindis=dis[v];
}
}
if(left==aug)
{
if(!(--gap[dis[src]]))dis[sourse]=nn;
dis[src]=mindis+1;
gap[dis[src]]++;
}
return aug-left;
}
int sap(int s,int e)
{
int ans=0;
nn=e+1;
memset(dis,0,sizeof(dis));
memset(gap,0,sizeof(gap));
gap[0]=nn;
sourse=s;
sink=e;
while(dis[sourse]<nn)
ans+=dfs(sourse,inf);
return ans;
}
bool search(long long mid)
{
s=0,t=n+n+1,nodes=0;
memset(head,-1,sizeof(head));
for(int i=1;i<=n;i++)
{
addedge(s,i,cow[i][0]);
addedge(i+n,t,cow[i][1]);
}
for(int i=1;i<=n;i++)
for(int j=1;j<=n;j++)
if(g[i][j]<=mid)
addedge(i,j+n,inf);
if(sap(s,t)==countt)return true;
return false;
}
long long solve()
{
long long l=0,r=maxx,mid,ans=-1;
while(l<=r)
{
mid=(l+r)>>1;
if(search(mid)){ans=mid;r=mid-1;}
else l=mid+1;
}
return ans;
}
int main()
{
int m;
while(scanf("%d%d",&n,&m)!=EOF)
{
init();
int a,b;
long long c;
for(int i=1;i<=n;i++)
{
scanf("%d%d",&cow[i][0],&cow[i][1]);
countt+=cow[i][0];
}
for(int i=1;i<=m;i++)
{
scanf("%d%d%lld",&a,&b,&c);
if(g[a][b]>c)g[a][b]=g[b][a]=c;
}
floyd();
maxx=findmin();
printf("%lld\n",solve());
}
return 0;
}
POJ 2391 Ombrophobic Bovines 二分拆点最大流+floyd(高精度)
原文:http://blog.csdn.net/crescent__moon/article/details/19827311