习题 2-10
用1,2,3,....,9组成3个三位数abc,def和ghi,每个数字恰好使用一次,要求abc:def:ghi=1:2:3。输出所有解。
#include <stdio.h> #include <stdlib.h> #include <string.h> int main(int argc, char *argv[]) { int abc, def, ghi; int a[10], count = 0; memset(a, 0, sizeof(a)); // printf("n\n"); for(abc = 123; abc <= 329; abc++) { def = 2*abc; ghi = 3*abc; a[abc/100] = a[abc/10%10] = a[abc%10] = 1; a[def/100] = a[def/10%10] = a[def%10] = 1; a[ghi/100] = a[ghi/10%10] = a[ghi%10] = 1; int i; for( i = 1; i <= 9; i++) count += a[i]; if(count == 9) printf("%d %d %d\n", abc, def, ghi); count = 0; memset(a, 0, sizeof(a)); } system("PAUSE"); return 0; }
2 判断过后,count和数组要清零。
算法竞赛入门经典 习题 2-10 排列(permutation)
原文:http://blog.csdn.net/oceaniwater/article/details/40709467