Container With Most Water
Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
SOLUTION 1:
采用2个指针一个在左一个在右，计算『桶』可以容纳的水。如果左边低，则左指针右移（试图看可不可以找到更高的bar），反之左移右指针
1 public class Solution { 2 public int maxArea(int[] height) { 3 if (height == null) { 4 return 0; 5 } 6 7 int left = 0; 8 int right = height.length - 1; 9 int maxArea = 0; 10 11 while (left < right) { 12 int h = Math.min(height[left], height[right]); 13 int area = h * (right - left); 14 maxArea = Math.max(maxArea, area); 15 16 if (height[left] < height[right]) { 17 // 如果左边界比较低，尝试向右寻找更高的边界 18 left++; 19 } else { 20 // 如果右边界比较低，尝试向左寻找更高的边界 21 right--; 22 } 23 } 24 25 return maxArea; 26 } 27 }
代码：
https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/twoPoints/MaxArea.java
LeetCode: Container With Most Water 解题报告
原文：http://www.cnblogs.com/yuzhangcmu/p/4057252.html
