首页 > 其他 > 详细

leetcode - Permutations II

时间:2014-10-23 12:27:41      阅读:234      评论:0      收藏:0      [点我收藏+]

Given a collection of numbers that might contain duplicates, return all possible unique permutations.

For example,
[1,1,2] have the following unique permutations:
[1,1,2][1,2,1], and [2,1,1].

class Solution {
public:
    std::vector<std::vector<int> > permuteUnique(std::vector<int> &num) {
		std::set<std::vector<int>> s;
		std::vector<std::vector<int>> res;
		std::sort(num.begin(),num.end());
		do
		{
			s.insert(num);
		} while (std::next_permutation(num.begin(),num.end()));
		for(std::set<std::vector<int>>::iterator it = s.begin(); it != s.end(); it++)
		{
			res.push_back(*it);
		}
		return res;
    }
};


leetcode - Permutations II

原文:http://blog.csdn.net/akibatakuya/article/details/40394055

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!