初始化
a = range(16)
a = np.array(a)
a = a.reshape(4,4)
- a
-
-
[[ 0 1 2 3]
[ 4 5 6 7]
[ 8 9 10 11]
[12 13 14 15]]
- 获取a的【0,1,4】行
-
- b = a[ range( 2)+range( 3, 4),:]
-
[[ 0 1 2 3]
[ 4 5 6 7]
[12 13 14 15]]
- 获取b的【0,1,4】列
-
- c = b[:, range( 1 )+range(2 , 3)]
-
[[ 0 2]
[ 4 6]
[12 14]]
python 有关矩阵行列的存取 np.array
原文：http://www.cnblogs.com/Dzhouqi/p/4040539.html
