============问题描述============
{
"address": "CN|\u5e7f\u4e1c|\u6df1\u5733|None|UNICOM|None|None",
"content": {
"address": "\u5e7f\u4e1c\u7701\u6df1\u5733\u5e02",
"address_detail": {
"city": "\u6df1\u5733\u5e02",
"city_code": 340,
"district": "",
"province": "\u5e7f\u4e1c\u7701",
"street": "",
"street_number": ""
},
"point": {
"x": "114.02597366",
"y": "22.54605355"
}
},
"status": 0
}
============解决方案1============
使用android提供的JSONArray data = new JSONArray(你的字符串);，再遍历这个data，转为JSONObject jsonObject = jsonArray.getJSONObject(i);在根据字段获取值int adkind = jsonObject.getInt(字段名);
============解决方案2============
try {
JSONObject jo = new JSONObject(json);
int status = jo.optInt("status");
String address = jo.optString("address");
JSONObject jo_point = jo.optJSONObject("point");
String x = jo_point.optString("x");
String y = jo_point.optString("y");
JSONObject jo_content = jo.optJSONObject("content");
String content_address = jo_content.optString("address");
JSONObject jo_detail = jo_content.optJSONObject("address_detail");
String city = jo_detail.optString("city");
int code = jo_detail.optInt("city_code");
String district = jo_detail.optString("district");
String province = jo_detail.optString("province");
String street = jo_detail.optString("street");
String street_number = jo_detail.optString("street_number");
} catch (JSONException e) {
e.printStackTrace();
}
============解决方案3============
[
============解决方案4============
这么标准的格式，用JSONObject那位大神帮忙JAVA解析JSON
原文：http://www.cnblogs.com/meizhenfen42/p/4033815.html
