NYOJ473 A^B Problem

原题链接

注意任何数的0次方都为1.

#include <cstdio>

int main(){
	int a, b;
	while(scanf("%d%d", &a, &b) == 2){
		if(b == 0){
			printf("1\n");
			continue;
		}
		b = (b - 1) % 4 + 1;
		int t = a = a % 10;
		for(int i = 1; i < b; ++i)
			a *= t;
		printf("%d\n", a % 10);
	}
	return 0;
}

NYOJ473 A^B Problem

原文：http://blog.csdn.net/chang_mu/article/details/19645715