LeetCode Maximum Product Subarray 解题报告

public class Solution {
    public int maxProduct(int A[]) {
        if(A==null||A.length==0) {
	      return 0;
	    }
	    int[][] productArray =  new int[A.length][A.length];
	    int maxProduct = A[0];
	    
	    for(int i=0;i<A.length;i++) {
	    	for(int j=i;j<A.length;j++) {
	    		if(j==i) {
	    		    productArray[i][i] = A[i];
	    		} else {
	    		    productArray[i][j] = productArray[i][j-1]*A[j];
	    		}
	    		if(productArray[i][j]>maxProduct) {
	    			maxProduct = productArray[i][i];
	    		}
	    	}
	    }
	    return maxProduct;
    }
}

public class Solution {
    public int maxProduct(int A[]) {
        if(A==null||A.length==0) {
	      return 0;
	    }
	    int maxProduct = A[0];
	    int max_temp   = A[0];
	    int min_temp   = A[0];
	    
	    for(int i=1;i<A.length;i++) {
	    	int a = A[i]*max_temp;
	    	int b = A[i]*min_temp;
	    	max_temp = Math.max(Math.max(a,b), A[i]);
	    	min_temp = Math.min(Math.min(a,b), A[i]);
	    	maxProduct = Math.max(maxProduct, max_temp);
	    }
	    return maxProduct;
    }
}

LeetCode Maximum Product Subarray 解题报告

原文：http://blog.csdn.net/worldwindjp/article/details/39826823