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[leetcode] Longest Valid Parentheses @python

时间:2014-10-01 02:18:00      阅读:378      评论:0      收藏:0      [点我收藏+]

Given a string containing just the characters ‘(‘ and ‘)‘, find the length of the longest valid (well-formed) parentheses substring.

For "(()", the longest valid parentheses substring is "()", which has length = 2.

Another example is ")()())", where the longest valid parentheses substring is "()()", which has length = 4.

 

class Solution:
    # @param s, a string
    # @return an integer
    def longestValidParentheses(self, s):
        #解题思路:返回括号串中合法括号串的长度。使用栈。这个解法比较巧妙,开辟一个栈,压栈的不是括号,而是未匹配左括号的索引!
        maxLen = 0
        stack = []
        last = -1
        for i in range(len(s)):
            if s[i] == (:
                stack.append(i)
            else:
                if stack == []:
                    last = i
                else:
                    stack.pop()
                    if stack == []:
                        maxLen = max(maxLen, i - last)
                    else:
                        maxLen = max(maxLen, i - stack[-1])
        return maxLen

 

[leetcode] Longest Valid Parentheses @python

原文:http://www.cnblogs.com/asrman/p/4002978.html

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