关于 Java 中 Collections.sort()方法 的使用<comparable 、 compareTo>
public static void main(String[] args) {
List<String> list = new ArrayList<String>();
list.add("abc");
list.add("abb");
list.add("bcd");
Collections.sort(list,new Comparator<String>() {
@Override
public int compare(String o1, String o2) {
/**
升序排序是 第一个参数.compareTo(第二个参数);
降序排序是 第二个参数.compareTo(第一个参数);
*/
return o2.compareTo(o1);
}
});
System.out.println(list);
}
输出: [bcd, abc, abb]
第一种:Comparable 排序接口
/* User实体类 */
public class User implements Comparable<User>{
private int id;
private String name;
private int age;
public User(){}
public User(int id, String name, int age) {
super();
this.id = id;
this.name = name;
this.age = age;
}
public int getId() { return id; }
public void setId(int id) { this.id = id; }
public String getName() { return name; }
public void setName(String name) { this.name = name; }
public int getAge() { return age; }
public void setAge(int age) { this.age = age; }
@Override
public int compareTo(User u) {
// 按age排序,也可按照其他成员变量排序
return this.age - u.getAge(); // 升序
// return u.getAge() - this.age; //降序
}
@Override
public String toString() {
return "User [id=" + id + ", name=" + name + ", age=" + age + "]";
}
}
/* Test测试类 */
ublic class Test {
public static void main(String[] args) {
List<User> list = new ArrayList<User>();
User user1 = new User(1,"aaaa",14);
User user2 = new User(2,"bbbb",21);
User user3 = new User(3,"cccc",12);
User user4 = new User(4,"dddd",16);
User user5 = new User(5,"eeee",9);
list.add(user1);
list.add(user2);
list.add(user3);
list.add(user4);
list.add(user5);
/*
list中的对象User实现了Comparable接口,含有compareTo()方法,
所以可以直接调用Collections.sort()方法进行排序
*/
Collections.sort(list);
System.out.println(list);
}
}
输出结果:[User [id=5, name=eeee, age=9], User [id=3, name=cccc, age=12], User [id=1, name=aaaa, age=14], User [id=4, name=dddd, age=16], User [id=2, name=bbbb, age=21]]
第二种:Comparator比较器接口
如果我们需要对某个类排序,但该类本身不支持排序(即没有实现Comparable接口),可使用Comparator比较器接口。
实体类不用实现Comparable接口
/* User实体类 */
public class User{
private int id;
private String name;
private int age;
public User(){}
public User(int id, String name, int age) {
super();
this.id = id;
this.name = name;
this.age = age;
}
public int getId() { return id; }
public void setId(int id) { this.id = id; }
public String getName() { return name; }
public void setName(String name) { this.name = name; }
public int getAge() { return age; }
public void setAge(int age) { this.age = age; }
@Override
public String toString() {
return "User [id=" + id + ", name=" + name + ", age=" + age + "]";
}
}
/* Test测试类 */
public class Test {
public static void main(String[] args) {
List<User> list = new ArrayList<User>();
User user1 = new User(1,"aaaa",14);
User user2 = new User(2,"bbbb",21);
User user3 = new User(3,"cccc",12);
User user4 = new User(4,"dddd",16);
User user5 = new User(5,"eeee",9);
list.add(user1);
list.add(user2);
list.add(user3);
list.add(user4);
list.add(user5);
/*
list中的对象User没有实现了Comparable接口,
通过重载Collections.sort()方法实现排序
*/
Collections.sort(list,new Comparator<User>() {
@Override
public int compare(User u1, User u2) {
//return u2.getAge()-u1.getAge(); // 降序
// return u1.getAge()-u2.getAge(); // 升序
return u2.getName().compareTo(u1.getName()); // 名字降序
}
});
System.out.println(list);
}
}
输出结果:[User [id=5, name=eeee, age=9], User [id=4, name=dddd, age=16], User [id=3, name=cccc, age=12], User [id=2, name=bbbb, age=21], User [id=1, name=aaaa, age=14]]
前者代码结构简单,但是只能根据固定的属性排序; 后者灵活,可以临时指定排序项,但是代码不够简洁
关于 Java 中 Collections.sort()方法 的使用
原文:https://www.cnblogs.com/Manan-vision/p/14789355.html