示例 1：输入：address = "1.1.1.1"输出："1[.]1[.]1[.]1"示例 2：输入：address = "255.100.50.0"输出："255[.]100[.]50[.]0"来源：力扣（LeetCode）链接：https://leetcode-cn.com/problems/defanging-an-ip-address著作权归领扣网络所有。商业转载请联系官方授权，非商业转载请注明出处。
class Solution(object): def defangIPaddr(self, address): """ :type address: str :rtype: str """ return address.replace(‘.‘,‘[.]‘)
class Solution(object): def defangIPaddr(self, address): """ :type address: str :rtype: str """ return "[.]".join(address.split("."))
class Solution(object): def defangIPaddr(self, address): """ :type address: str :rtype: str """ r_str = "" for ch in address: if ch == ".": r_str = r_str + ‘[.]‘ else: r_str = r_str + ch return r_str
各位大神，有其他思路欢迎留言~
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csdn：https://blog.csdn.net/ccgshigao
原文：https://www.cnblogs.com/qa-freeroad/p/14153145.html