1486. XOR Operation in an Array
设置rat = num = start,从1开始做循环到n-1,先计算num = start + 2*i,然后用计算rat^=num,最后返回rat。
时间复杂度:O(n)
空间复杂度:O(1)
class Solution:
    def xorOperation(self, n: int, start: int) -> int:
        rat = num = start
        for i in range(1, n):
            num = start + 2 * i
            rat ^= num
        return rat
LeetCode #1486. XOR Operation in an Array
原文:https://www.cnblogs.com/RatsCommander/p/14072208.html