java 红包案例 小白 不是最好方案 添加成员需要new 还得调收红包的方法 不调不会收
//父类 群类
public class Group {
    private String name;//名字
    private String position;//职位
    private double balance;//余额
    static int memberNum;//人数
    //构造方法
    public Group() {
    }
    public Group(String name, String position, double balance) {
        this.name = name;
        this.position = position;
        this.balance = balance;
    }
    //getXxx() setXxx()
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public String getPosition() {
        return position;
    }
    public void setPosition(String position) {
        this.position = position;
    }
    public double getBalance() {
        return balance;
    }
    public void setBalance(double balance) {
        this.balance = balance;
    }
}
//群主类 继承群类
import java.util.ArrayList;
import java.util.Random;
public class GroupOwner extends Group {
    static ArrayList<Double> arrPart = new ArrayList<>();//把发出来的随机红包金额 赋给arrPart数组
    //构造方法
    public GroupOwner() {
    }
    public GroupOwner(String name, String position, double balance) {
        this.setName(name);
        this.setPosition(position);
        this.setBalance(balance);
    }
    //发红包方法  参数有钱和要发几份
    public void giveRedEnvelopes(double money, int numPeople) {
        //发的钱从群主余额扣除
        setBalance(getBalance() - money);
        //初始化
        arrPart = new ArrayList<>();
        double aceilingName = 0;//不能超出传来的money总数
        for (int i = 0; i < numPeople; i++) {//用份数当循环条件  可以人少份数多
            Random random = new Random();
            //随机多少钱 随机条件是 发的钱数/份数*2 公平点(随机)
            double nextInt = random.nextDouble() * (money / numPeople*2);
            if (aceilingName >= money) {//发的份数的总钱数大于总钱数 退出
                break;
            } else if (i == numPeople - 1) {//最后一份 把剩下的全拿走
                arrPart.add(money - aceilingName);
            } else {//其他随机
                arrPart.add(nextInt);
            }
            aceilingName += nextInt;//叠加 发出去的份数 和钱数
        }
        System.out.println(getName() + "群主发了:" + money);
        for (int i = 0; i < arrPart.size(); i++) {//遍历 随机红包金额的钱 数组 展示红包
            if (i == arrPart.size()) {//防止越界
                System.out.println("第" + i + "个红包为:" + arrPart.get(i));
                break;
            } else {
                System.out.println("第" + (i + 1) + "个红包为:" + arrPart.get(i));//索引对应红包数,索引从0开始所以要+1
            }
        }
    }
}
//成员类
import java.util.ArrayList;
import java.util.Random;
public class Member extends Group {
    static ArrayList<Double> max = new ArrayList<>();//这个数组用来存储接收的红包钱数判断谁是手气王
    static ArrayList<String> name = new ArrayList<>();//这个数组用来存储名字的
    //构造方法
    public Member() {
    }
    public Member(String name, String position, double balance) {
        Group.memberNum++;//调一次全参构造群人数就加一
        this.setName(name);
        this.setPosition(position);
        this.setBalance(balance);
    }
    //收红包方法
    public void receiveLuckyMoney() {
        double remove = 0;
        //遍历 群主发的红包数组
        for (int i = 0; i < GroupOwner.arrPart.size(); i++) {
            //随即索引 取出 对应的红包
            int nextInt = new Random().nextInt(GroupOwner.arrPart.size());
            //取出 删除 返回值为:获取的钱数
            remove = GroupOwner.arrPart.remove(nextInt);
            //调一次就把获得的余额 和姓名 传给对应的数组
            max.add(remove);
            name.add(getName());
            //领取后把钱加到自己的余额中
            setBalance(getBalance() + remove);
            System.out.println(getName() + "领取了:" + remove + "元" + "。现在余额为:" + getBalance() + "元");
            break;
        }
    }
}
//测试 群 类
import java.util.Scanner;
public class TestGroup {
    public static void main(String[] args) {
        //构造群主
        GroupOwner groupOwner = new GroupOwner("张三", "群主", 5000);
        //构造成员
        Member member01 = new Member("李四", "成员", 500);
        Member member02 = new Member("王五", "成员", 700);
        Member member03 = new Member("赵六", "成员", 888);
        Member member04 = new Member("田七", "成员", 999);
        System.out.println("群里人数为:" + Group.memberNum);
        //发多少钱红包和个数
        Scanner scanner = new Scanner(System.in);
        System.out.println("输入发多少钱:");
        double money = scanner.nextDouble();
        System.out.println("发几份:");
        int peopleNum = scanner.nextInt();
        groupOwner.giveRedEnvelopes(money, peopleNum);
        //收红包
        member01.receiveLuckyMoney();
        member02.receiveLuckyMoney();
        member03.receiveLuckyMoney();
        member04.receiveLuckyMoney();
        //手气王
        double temp = 0;//max 获得的红包钱数的中间变量
        String maxName;//name 名字要随着红包变化而变化 就可以实现一一对应
        //排序 降序 第一个索引就为最大值 名字和钱数一起变 所以就可以一一对应起来了
        for (int i = 0; i < Member.max.size(); i++) {
            for (int j = 0; j < Member.max.size() - 1; j++) {
                if (Member.max.get(j) < Member.max.get(j + 1)) {
                    temp = Member.max.get(j);
                    Member.max.set(j, Member.max.get(j + 1));
                    Member.max.set(j + 1, temp);
                    //随着余额索引变化 而变化
                    maxName = Member.name.get(j);
                    Member.name.set(j, Member.name.get(j + 1));
                    Member.name.set(j + 1, maxName);
                }
            }
        }
        System.out.println("手气王为:" + Member.name.get(0) + "  抽取了:" + Member.max.get(0) + "元");
    }
}
 
 
 java 红包案例 不是最好方案 添加成员需要new 还得调收红包的方法 不调不会收
原文:https://www.cnblogs.com/shangjinshuai/p/14018581.html