int main()
    {
    int i = 0;
    int count = 0;
    for (i = 1; i <= 100; i++)
    {
        if (i % 3 == 0)
        {
            printf("%d ", i);
                count++;
        }
    }
    printf("\nconut=%d\n", count);
    return 0;
}运行结果

解法二
```
int main(){
int a = 1;
int count = 0;
while (a <= 100)
{
if (a % 3 == 0)
{
printf("%d ", a);
a++;
count++;
}
else
a++;
}
printf("\nconut=%d\n", count);
return 0;
}
运行结果
原文:https://blog.51cto.com/14950896/2545747