二叉树遍历

Go代码同时使用递归和迭代实现二叉树遍历

package main

import (
	"fmt"
)

type TreeNode struct {
	Val         int
	Left, Right *TreeNode
}

type stack []TreeNode

func (s stack) Push(t TreeNode) stack {
	return append(s, t)
}

func (s stack) Pop() (stack, TreeNode) {
	return s[:len(s)-1], s[len(s)-1]
}

func (s stack) IsEmpty() bool {
	return len(s) == 0
}

type queue []TreeNode

func (q queue) Enqueue(t TreeNode) queue {
	return append(q, t)
}

func (q queue) Dequeue() (queue, TreeNode) {
	return q[1:], q[0]
}

func (q queue) IsEmpty() bool {
	return len(q) == 0
}

func PreOrderRecur(t *TreeNode) {
	if t == nil {
		return
	}
	fmt.Println(t.Val)
	PreOrderRecur(t.Left)
	PreOrderRecur(t.Right)
}

func PreOrder(t *TreeNode) {
	if t == nil {
		return
	}

	var s stack
	cur := t
	for !s.IsEmpty() || cur != nil {
		if cur != nil {
			fmt.Println(cur.Val)
			s = s.Push(*cur)
			cur = cur.Left
		} else {
			s, *cur = s.Pop()
			cur = cur.Right
		}
	}
	// s = s.Push(*cur)
	// for !s.IsEmpty() {
	// 	s, *cur = s.Pop()
	// 	fmt.Println(cur.Val)
	// 	if cur.Right != nil {
	// 		s = s.Push(*cur.Right)
	// 	}
	// 	if cur.Left != nil {
	// 		s = s.Push(*cur.Left)
	// 	}
	// }
}

func InOrderRecur(t *TreeNode) {
	if t == nil {
		return
	}
	InOrderRecur(t.Left)
	fmt.Println(t.Val)
	InOrderRecur(t.Right)
}

func InOrder(t *TreeNode) {
	if t == nil {
		return
	}

	var s stack
	cur := t
	for !s.IsEmpty() || cur != nil {
		if cur != nil {
			s = s.Push(*cur)
			cur = cur.Left
		} else {
			s, *cur = s.Pop()
			fmt.Println(cur.Val)
			cur = cur.Right
		}
	}
}

func PostOrderRecur(t *TreeNode) {
	if t == nil {
		return
	}

	PostOrderRecur(t.Left)
	PostOrderRecur(t.Right)
	fmt.Println(t.Val)
}

func PostOrder(t *TreeNode) {
	if t == nil {
		return
	}

	var s1, s2 stack
	s1 = s1.Push(*t)
	cur := t
	for !s1.IsEmpty() {
		s1, *cur = s1.Pop()
		if cur.Left != nil {
			s1 = s1.Push(*cur.Left)
		}
		if cur.Right != nil {
			s1 = s1.Push(*cur.Right)
		}
		s2 = s2.Push(*cur)
	}
	for !s2.IsEmpty() {
		s2, *cur = s2.Pop()
		fmt.Println(cur.Val)
	}
}

func LevelOrder(t *TreeNode) {
	if t == nil {
		return
	}

	var q queue
	node := t
	q = q.Enqueue(*t)
	for !q.IsEmpty() {
		q, *node = q.Dequeue()
		fmt.Println(node.Val)
		if node.Left != nil {
			q = q.Enqueue(*node.Left)
		}
		if node.Right != nil {
			q = q.Enqueue(*node.Right)
		}
	}
}

二叉树遍历

原文：https://www.cnblogs.com/jeffrey-yang/p/13605210.html