https://vjudge.net/problem/HDU-6879
题意:
给定S,r,c
构造一个r行c列的阵列。
对于没有炸弹的位置的数值为位置附近8个位置炸弹总数
保证炸弹总数S
代码:
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<bitset>
#include<cassert>
#include<cctype>
#include<cmath>
#include<cstdlib>
#include<ctime>
#include<deque>
#include<iomanip>
#include<list>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<vector>
#include <vector>
#include <iterator>
#include <utility>
#include <sstream>
#include <limits>
#include <numeric>
#include <functional>
using namespace std;
#define gc getchar()
#define mem(a) memset(a,0,sizeof(a))
#define debug(x) cout<<"debug:"<<#x<<" = "<<x<<endl;
#define ios ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int,int> pii;
typedef char ch;
typedef double db;
const double PI=acos(-1.0);
const double eps=1e-6;
const int inf=0x3f3f3f3f;
const int maxn=1e5+10;
const int maxm=100+10;
const int N=1e6+10;
const int mod=1e9+7;
const int dir[8][2] = {1, 0, 0, 1, -1, 0, 0, -1, -1, -1, -1, 1, 1, -1, 1, 1};
map< int, vector< vector<char> > > M;
int n = 0;
int main()
{
srand((int) time(0));
int T = 0;
cin >> T;
int random = 0;
int chg = 0;
for (int I = 1; I<=50000;I++)
{
random = (rand() % 25) + 1;
chg = (rand() % 25) + 1;
vector< vector<char> > A(random, vector<char>(chg));
for(int i = 0;i<random;i++)
{
for(int j = 0;j<chg;j++)
{
if((rand()%2))
{
A[i][j] = ‘X‘;
}
else
{
A[i][j] = ‘.‘;
}
}
}
random = A.size();
chg = A[0].size();
int S = 0;
for(int i = 0;i<random;i++)
{
for(int j = 0;j<chg;j++)
{
if (A[i][j] == ‘.‘)
{
int counter = 0;
for (int L = 0;L<8;L++)
{
int dx = i + dir[L][0];
int dy = j + dir[L][1];
if ( (dx >= 0 && dx <= random-1) && (dy >= 0 && dy <= chg-1) )
{
if(A[dx][dy] == ‘X‘)
{
counter++;
}
}
}
S += counter;
}
}
}
M[S] = A;
}
while(T--)
{
cin >> n;
vector< vector<char> > A = M[n];
random = A.size();
chg = A[0].size();
cout << random << " " << chg << endl;
for (int i = 0;i<random;i++)
{
for (int j = 0;j<chg;j++)
{
cout << A[i][j];
if(j == chg - 1) cout << endl;
}
}
}
return 0;
}
原文:https://www.cnblogs.com/SutsuharaYuki/p/13562233.html