1 bool hasPathSum(TreeNode* root, int sum) { 2 if(root == NULL) 3 return false; 4 sum -= root->val; 5 if(root->left == NULL && root->right == NULL && sum == 0) 6 return true; 7 else 8 return hasPathSum(root->left, sum) || hasPathSum(root->right, sum); 9 }
原文:https://www.cnblogs.com/qingjiaowoxiaoxioashou/p/13512468.html