leetcode-----131. 分割回文串

• 链接：https://leetcode-cn.com/problems/palindrome-partitioning/

代码

/*
 * @lc app=leetcode.cn id=131 lang=cpp
 *
 * [131] 分割回文串
 */

// @lc code=start
class Solution {
public:
    vector<vector<bool>> f;
    vector<vector<string>> ans;
    vector<string> path;

    vector<vector<string>> partition(string s) {
        int n = s.size();
        f = vector<vector<bool>>(n, vector<bool>(n));
        for (int j = 0; j < n; j++) {
            for (int i = 0; i <= j; i++) {
                if (i == j) f[i][j] = true;
                else if (s[i] == s[j]) {
                    if (i + 1 > j - 1 || f[i + 1][j - 1]) f[i][j] = true;
                }
            }
        }
        dfs(s, 0);
        return ans;
    }

    void dfs(string s, int u) {
        if (u == s.size()) ans.push_back(path);
        else {
            for (int i = u; i < s.size(); i++) {
                if (f[u][i]) {
                    path.push_back(s.substr(u, i - u + 1));
                    dfs(s, i + 1);
                    path.pop_back();
                }
            }
        }
    }
};
// @lc code=end

leetcode-----131. 分割回文串

原文：https://www.cnblogs.com/clown9804/p/13406649.html