首页 > 编程语言 > 详细

Java中HashMap的putAll()方法: HashMap.putAll() - Break易站

时间:2020-07-13 23:42:11      阅读:77      评论:0      收藏:0      [点我收藏+]
[
  • ??Java中的HashMap

    Java.util.HashMap.putAll()是HashMap类的内置方法,用于复制操作。该方法将所有元素(即映射)从一个映射复制到另一个映射。

    句法:

    new_hash_map.putAll(exist_hash_map)

    参数:该方法采用一个参数exist_hash_map,该参数引用我们要复制的现有HashMap

    返回值:该方法不返回任何值。

    异常:如果我们要复制的映射为NULL,则该方法抛出NullPointerException

    下面的程序说明了java.util.HashMap.putAll()方法的工作原理

    程序1:将字符串值映射到整数键。

    // Java code to illustrate the putAll() method
    import java.util.*;
    
    public class Hash_Map_Demo {
    public static void main(String[] args) {
    ?????
    ????// Creating an empty HashMap
    ????HashMap<Integer, String> hash_map = new HashMap<Integer, String>();
    
    ????// Mapping string values to int keys
    ????hash_map.put(10, "Geeks");
    ????hash_map.put(15, "4");
    ????hash_map.put(20, "Geeks");
    ????hash_map.put(25, "Welcomes");
    ????hash_map.put(30, "You");
    
    ????// Displaying the HashMap
    ????System.out.println("Initial Mappings are: " + hash_map);
    
    ????// Creating a new hash map and copying
    ????HashMap<Integer, String> new_hash_map = new HashMap<Integer, String>();
    ????new_hash_map.putAll(hash_map);
    
    ????// Displaying the final HashMap
    ????System.out.println("The new map looks like this: " + new_hash_map);
    }
    }
    

    输出:

    Initial Mappings are: {20=Geeks, 25=Welcomes, 10=Geeks, 30=You, 15=4}
    The new map looks like this: {25=Welcomes, 10=Geeks, 20=Geeks, 30=You, 15=4}

    程序2:将整数值映射到字符串键。

    // Java code to illustrate the putAll() method
    import java.util.*;
    
    public class Hash_Map_Demo {
    ????public static void main(String[] args)
    ????{
    
    ????????// Creating an empty HashMap
    ????????HashMap<String, Integer> hash_map = new HashMap<String, Integer>();
    
    ????????// Mapping int values to string keys
    ????????hash_map.put("Geeks", 10);
    ????????hash_map.put("4", 15);
    ????????hash_map.put("Geeks", 20);
    ????????hash_map.put("Welcomes", 25);
    ????????hash_map.put("You", 30);
    
    ????????// Displaying the HashMap
    ????????System.out.println("Initial Mappings are: " + hash_map);
    
    ????????// Creating a new hash map and copying
    ????????HashMap<String, Integer> new_hash_map = new HashMap<String, Integer>();
    ????????new_hash_map.putAll(hash_map);
    
    ????????// Displaying the final HashMap
    ????????System.out.println("The new map looks like this: " + new_hash_map);
    ????}
    }
    

    输出:

    Initial Mappings are: {4=15, Geeks=20, You=30, Welcomes=25}
    The new map looks like this: {Geeks=20, 4=15, You=30, Welcomes=25}

    注意:对于具有不同数据类型的变体和组合的任何类型的映射,都可以执行相同的操作。

  • ??Java中的HashMap
    ]
    转载请保留页面地址:https://www.breakyizhan.com/java/5443.html

    Java中HashMap的putAll()方法: HashMap.putAll() - Break易站

    原文:https://www.cnblogs.com/breakyizhan/p/13296111.html

    (0)
    (0)
       
    举报
    评论 一句话评论(0
    关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
    © 2014 bubuko.com 版权所有
    打开技术之扣,分享程序人生!