首页 > 其他 > 详细

常见函数方法解析

时间:2020-06-23 23:46:54      阅读:83      评论:0      收藏:0      [点我收藏+]
技术分享图片
 1 python路径拼接os.path.join()函数的用法
 2 os.path.join()函数:连接两个或更多的路径名组件
 3 
 4                          1.如果各组件名首字母不包含’/’,则函数会自动加上
 5 
 6          2.如果有一个组件是一个绝对路径,则在它之前的所有组件均会被舍弃
 7 
 8          3.如果最后一个组件为空,则生成的路径以一个’/’分隔符结尾
 9 
10 Demo1
11 import os
12 
13 Path1 = home
14 Path2 = develop
15 Path3 = code
16 
17 Path10 = Path1 + Path2 + Path3
18 Path20 = os.path.join(Path1,Path2,Path3)
19 print (Path10 = ,Path10)
20 print (Path20 = ,Path20)
21 
22 输出
23 
24  
25 
26 Path10 = homedevelopcode
27 Path20 = home\develop\code
28 
29  
30 
31 --------------------------------------------------------------
32 
33  
34 
35 Demo2
36  
37 
38 import os
39 
40 Path1 = /home
41 Path2 = develop
42 Path3 = code
43 
44 Path10 = Path1 + Path2 + Path3
45 Path20 = os.path.join(Path1,Path2,Path3)
46 print (Path10 = ,Path10)
47 print (Path20 = ,Path20) 
48 输出
49 
50 Path10 = /homedevelopcode
51 Path20 = /home\develop\code
52 
53 --------------------------------------------------------------
54 
55 Demo3
56 import os
57 
58 Path1 = home
59 Path2 = /develop
60 Path3 = code
61 
62 Path10 = Path1 + Path2 + Path3
63 Path20 = os.path.join(Path1,Path2,Path3)
64 print (Path10 = ,Path10)
65 print (Path20 = ,Path20) 
66 
67 输出
68 
69 Path10 = home/developcode
70 Path20 = /develop\code
71 
72 --------------------------------------------------------------
73 
74 Demo4
75 import os
76 
77 Path1 = home
78 Path2 = develop
79 Path3 = /code
80 
81 Path10 = Path1 + Path2 + Path3
82 Path20 = os.path.join(Path1,Path2,Path3)
83 print (Path10 = ,Path10)
84 print (Path20 = ,Path20 )
85 
86 输出
87 
88 Path10 = homedevelop/code
89 Path20 = /code
os.path.join

 

常见函数方法解析

原文:https://www.cnblogs.com/tianqi6012/p/13184910.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!