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动态二维数组实现

时间:2020-06-14 17:14:16      阅读:49      评论:0      收藏:0      [点我收藏+]
二维动态数组和静态数组的存储方式如下:

技术分享图片

 二维动态数组代码实现如下:

#include <stdio.h>
#define DEBUG
int matrixMultiplication(int n, int **A, int **B, int s, int t){
    int result = 0;
    for (int i = 0; i < n; i++){
        result += A[s][i] * B[i][t];
#ifdef DEBUG
        printf("result:%d, A[s][i]:%d, b[i][t]:%d\n", result, A[s][i], B[i][t]);
#endif
    }
    return result;
}

int main(){
    int n = 5;
    int **A = new int*[n];
    int k = 0;
    int **B = new int*[n];
    for (int i = 0; i < n; i++){
        A[i] = new int[n];
        B[i] = new int[n];
    }
    for (int i = 0; i < n; i++){
        for(int j = 0; j < n; j++){
            B[i][j] = -k;
            A[i][j] = k++;
        }
    }
#ifdef DEBUG
    printf("A:\n");
    for (int i = 0; i < n; i++){
        for(int j = 0; j < n; j++){
            printf("%d ", A[i][j]);
        }
        printf("\n");
    }
    printf("B:\n");
    for (int i = 0; i < n; i++){
        for (int j = 0; j < n; j++){
            printf("%d ", B[i][j]);
        }
        printf("\n");
    }
#endif
    for (int i = 0; i < n; i++){
        delete[] A[i];
        delete[] B[i];
    }
    delete[] A;
    delete[] B;
    int result = matrixMultiplication(n, A, B, 2, 3);
    printf("%d\n", result);
}

 

动态二维数组实现

原文:https://www.cnblogs.com/feng-ying/p/13125378.html

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