SUBSTRING / CHARINDEX_函数随手练_2

/*
     Learning SQL on SQL Server2005
*/

--要将名字中带有空格的，使用空格前面部分内容，加上一个 ， 再加空格后面的第1个字符
--    名字中不带空格的，直接使用名字的全部内容，加上一个， (有待继续)

SELECT *
FROM Production.Location
---------------------------------
SELECT NAME,
               Len(NAME) AS [Len(name)],
              -- "First letter of name 1" = Substring(NAME, 0, 2),       --注释掉这3句，仅为熟悉下 
              -- "First letter of name 2" = Substring(NAME, 1, 1),       
              -- "First letter of name 3" = Substring(NAME, -1, 3),      
               "Position of Space in Employee names" = Charindex(‘ ‘, NAME),
               "Position of Space in Employee names" = Substring(NAME, 1, Charindex(‘ ‘, NAME)-1)
                                                       + ‘, ‘
                                                       + Substring(NAME, Charindex(‘ ‘, NAME)+1, 1)
                                                       + ‘.‘
FROM   Production.Location
WHERE  Charindex(‘ ‘, NAME) <> 0