https://leetcode-cn.com/problems/dui-lie-de-zui-da-zhi-lcof/
基本思路就是4,3,2,5这个队里,如果5出现了,那么前面的数字的max就都是5了,所以维护一个双端队列把5出现后,前面的4个都清理掉
import java.util.Deque;
import java.util.LinkedList;
class MaxQueue {
private Deque<Integer> queue = new LinkedList<>();
private Deque<Integer> maxQueue = new LinkedList<>();
public MaxQueue() {
}
public int max_value() {
if(maxQueue.size() > 0) {
return maxQueue.peekFirst();
}
return -1;
}
public void push_back(int value) {
queue.addLast(value);
while (maxQueue.size() > 0 && maxQueue.peekLast() < value) {//删掉队尾比他小的,比如4,3,2,1的maxQueue也是4,3,2,1,如果这个时候插入一个53,那么2,1就没用了
maxQueue.pollLast();
}
maxQueue.addLast(value);
}
public int pop_front() {
if(queue.size() > 0) {
int value = queue.poll();
if (maxQueue.peekFirst() == value) {
maxQueue.poll();
}
return value;
}
return -1;
}
}
/**
* Your MaxQueue object will be instantiated and called as such:
* MaxQueue obj = new MaxQueue();
* int param_1 = obj.max_value();
* obj.push_back(value);
* int param_3 = obj.pop_front();
*/
原文:https://www.cnblogs.com/iamzhoug37/p/12970059.html