Given a string s consists of upper/lower-case alphabets and empty space characters ‘
‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
思路：将字符串分割成单词，然后返回最后一个的长度即可
class Solution:
# @param s, a string
# @return an integer
def lengthOfLastWord(self, s):
s_split = s.split()
return 0 if len(s_split) == 0 else len(s_split[-1])
Leetcode 细节实现 Length of Last Word
原文：http://blog.csdn.net/zhengsenlie/article/details/39120191