python - 输出目录结构

import os


def rev(path: str, i=0):
    s = ‘+‘ * i + path.split(‘/‘)[-1] + ‘\n‘
    for _ in os.listdir(path):
        if os.path.isdir(path + ‘/‘ + _):
            s += rev(path + ‘/‘ + _, i + 1) + ‘\n‘
        elif os.path.isfile(path + ‘/‘ + _):
            s += ‘+‘ + ‘+‘ * i + _ + ‘\n‘
    return s


print(rev(‘D:/PycharmProjects‘))