python中的字典底层是树实现的，本身没有像列表一样可以排序，但是会有应用场景需要将字典排序
d = {‘lilee‘:25, ‘wangyan‘:21, ‘liqun‘:32, ‘age‘:19}
print(sorted(d.items(), key=lambda item:item[1]))
# response:
# [(‘age‘, 19), (‘wangyan‘, 21), (‘lilee‘, 25), (‘liqun‘, 32)]
2、列表嵌套字典，列表里存在多个字典，需要按照某一个键值对排序
response = [ {‘pId‘: ‘/opt/data/‘, ‘id‘: ‘/opt/data/1.txt‘, ‘name‘: ‘1.txt‘}, {‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04/data-2020-04-01-1.log.gz‘, ‘name‘: ‘2020-04/data-2020-04-01-1.log.gz‘}, {‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04/data-2020-04-02-1.log.gz‘, ‘name‘: ‘2020-04/data-2020-04-02-1.log.gz‘}, {‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04/data-2020-04-04-1.log.gz‘, ‘name‘: ‘2020-04/data-2020-04-04-1.log.gz‘}, {‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04/data-2020-04-03-1.log.gz‘, ‘name‘: ‘2020-04/data-2020-04-03-1.log.gz‘}, {‘name‘: ‘2020-04‘, ‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04‘}, {‘pId‘: ‘/opt/data/‘, ‘id‘: ‘/opt/data/data.log‘, ‘name‘: ‘data.log‘}, ] response.sort(key=lambda x: x[‘id‘]) print(response) # [{‘pId‘: ‘/opt/data/‘, ‘id‘: ‘/opt/data/1.txt‘, ‘name‘: ‘1.txt‘}, {‘name‘: ‘2020-04‘, ‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04‘}, {‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04/data-2020-04-01-1.log.gz‘, ‘name‘: ‘2020-04/data-2020-04-01-1.log.gz‘}, {‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04/data-2020-04-02-1.log.gz‘, ‘name‘: ‘2020-04/data-2020-04-02-1.log.gz‘}, {‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04/data-2020-04-03-1.log.gz‘, ‘name‘: ‘2020-04/data-2020-04-03-1.log.gz‘}, {‘pId‘: ‘/opt/data/2020-04‘, ‘id‘: ‘/opt/data/2020-04/data-2020-04-04-1.log.gz‘, ‘name‘: ‘2020-04/data-2020-04-04-1.log.gz‘}, {‘pId‘: ‘/opt/data/‘, ‘id‘: ‘/opt/data/data.log‘, ‘name‘: ‘data.log‘}]
原文：https://www.cnblogs.com/lutt/p/12723267.html