正则表达式-C语言下调用API

 1 #include <sys/types.h>
 2 #include <regex.h>
 3 
 4 int regcomp(regex_t *preg, const char *regex, int cflags);
 5 
 6 int regexec(const regex_t *preg, const char *string, size_t nmatch,
 7            regmatch_t pmatch[], int eflags);
 8 
 9 size_t regerror(int errcode, const regex_t *preg, char *errbuf,
10                size_t errbuf_size);
11 
12 void regfree(regex_t *preg);

#include <stdio.h>
#include <string.h>
#include <regex.h>
 
// 提取子串
char* getsubstr(char *s, regmatch_t *pmatch)
{
    static char buf[100] = {0};
    memset(buf, 0, sizeof(buf));
    memcpy(buf, s+pmatch->rm_so, pmatch->rm_eo - pmatch->rm_so);
 
    return buf;
}
 
int main(void)
{
    regmatch_t pmatch;
    regex_t reg;
    //const char *pattern = "[a-z]+";        // 正则表达式
    //char buf[] = "HELLOsaiYear2012@gmail.com";    // 待搜索的字符串
    
    const char *pattern = "[a-zA-Z_#+]+";        // 正则表达式
    char buf[] = "adc/+/Request/#/MODBUS/mb1";    // 待搜索的字符串
 
    regcomp(&reg, pattern, REG_EXTENDED);    //编译正则表达式
    int offset = 0;
     while(offset < strlen(buf))
    {
        int status = regexec(&reg, buf + offset, 1, &pmatch, 0);
        /* 匹配正则表达式，注意regexec()函数一次只能匹配一个，不能连续匹配，网上很多示例并没有说明这一点 */
        if(status == REG_NOMATCH)
            printf("No Match\n");
        else if(pmatch.rm_so != -1)
        {
            printf("Match:\n");
            char *p = getsubstr(buf + offset, &pmatch);
             printf("[%d, %d]: %s\n", offset + pmatch.rm_so + 1, offset + pmatch.rm_eo, p);
        }
        offset += pmatch.rm_eo;
    }
    regfree(&reg);        //释放正则表达式
 
    return 0;
}