// 面试题54:二叉搜索树的第k个结点 // 题目:给定一棵二叉搜索树,请找出其中的第k大的结点。 #include <cstdio> #include "BinaryTree.h" const BinaryTreeNode* KthNodeCore(const BinaryTreeNode* pRoot, unsigned int& k); const BinaryTreeNode* KthNode(const BinaryTreeNode* pRoot, unsigned int k) { if (pRoot == nullptr || k == 0) return nullptr; return KthNodeCore(pRoot, k); } const BinaryTreeNode* KthNodeCore(const BinaryTreeNode* pRoot, unsigned int& k) { const BinaryTreeNode* target = nullptr; if (pRoot->m_pLeft != nullptr) target = KthNodeCore(pRoot->m_pLeft, k); if (target == nullptr) { if (k == 1) target = pRoot; k--; } if (target == nullptr && pRoot->m_pRight != nullptr) target = KthNodeCore(pRoot->m_pRight, k); return target; }
// ====================测试代码==================== void Test(const char* testName, const BinaryTreeNode* pRoot, unsigned int k, bool isNull, int expected) { if (testName != nullptr) printf("%s begins: ", testName); const BinaryTreeNode* pTarget = KthNode(pRoot, k); if ((isNull && pTarget == nullptr) || (!isNull && pTarget->m_nValue == expected)) printf("Passed.\n"); else printf("FAILED.\n"); } // 8 // 6 10 // 5 7 9 11 void TestA() { BinaryTreeNode* pNode8 = CreateBinaryTreeNode(8); BinaryTreeNode* pNode6 = CreateBinaryTreeNode(6); BinaryTreeNode* pNode10 = CreateBinaryTreeNode(10); BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); BinaryTreeNode* pNode7 = CreateBinaryTreeNode(7); BinaryTreeNode* pNode9 = CreateBinaryTreeNode(9); BinaryTreeNode* pNode11 = CreateBinaryTreeNode(11); ConnectTreeNodes(pNode8, pNode6, pNode10); ConnectTreeNodes(pNode6, pNode5, pNode7); ConnectTreeNodes(pNode10, pNode9, pNode11); Test("TestA0", pNode8, 0, true, -1); Test("TestA1", pNode8, 1, false, 5); Test("TestA2", pNode8, 2, false, 6); Test("TestA3", pNode8, 3, false, 7); Test("TestA4", pNode8, 4, false, 8); Test("TestA5", pNode8, 5, false, 9); Test("TestA6", pNode8, 6, false, 10); Test("TestA7", pNode8, 7, false, 11); Test("TestA8", pNode8, 8, true, -1); DestroyTree(pNode8); printf("\n\n"); } // 5 // / // 4 // / // 3 // / // 2 // / // 1 void TestB() { BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); BinaryTreeNode* pNode3 = CreateBinaryTreeNode(3); BinaryTreeNode* pNode2 = CreateBinaryTreeNode(2); BinaryTreeNode* pNode1 = CreateBinaryTreeNode(1); ConnectTreeNodes(pNode5, pNode4, nullptr); ConnectTreeNodes(pNode4, pNode3, nullptr); ConnectTreeNodes(pNode3, pNode2, nullptr); ConnectTreeNodes(pNode2, pNode1, nullptr); Test("TestB0", pNode5, 0, true, -1); Test("TestB1", pNode5, 1, false, 1); Test("TestB2", pNode5, 2, false, 2); Test("TestB3", pNode5, 3, false, 3); Test("TestB4", pNode5, 4, false, 4); Test("TestB5", pNode5, 5, false, 5); Test("TestB6", pNode5, 6, true, -1); DestroyTree(pNode5); printf("\n\n"); } // 1 // // 2 // // 3 // // 4 // // 5 void TestC() { BinaryTreeNode* pNode1 = CreateBinaryTreeNode(1); BinaryTreeNode* pNode2 = CreateBinaryTreeNode(2); BinaryTreeNode* pNode3 = CreateBinaryTreeNode(3); BinaryTreeNode* pNode4 = CreateBinaryTreeNode(4); BinaryTreeNode* pNode5 = CreateBinaryTreeNode(5); ConnectTreeNodes(pNode1, nullptr, pNode2); ConnectTreeNodes(pNode2, nullptr, pNode3); ConnectTreeNodes(pNode3, nullptr, pNode4); ConnectTreeNodes(pNode4, nullptr, pNode5); Test("TestC0", pNode1, 0, true, -1); Test("TestC1", pNode1, 1, false, 1); Test("TestC2", pNode1, 2, false, 2); Test("TestC3", pNode1, 3, false, 3); Test("TestC4", pNode1, 4, false, 4); Test("TestC5", pNode1, 5, false, 5); Test("TestC6", pNode1, 6, true, -1); DestroyTree(pNode1); printf("\n\n"); } // There is only one node in a tree void TestD() { BinaryTreeNode* pNode1 = CreateBinaryTreeNode(1); Test("TestD0", pNode1, 0, true, -1); Test("TestD1", pNode1, 1, false, 1); Test("TestD2", pNode1, 2, true, -1); DestroyTree(pNode1); printf("\n\n"); } // empty tree void TestE() { Test("TestE0", nullptr, 0, true, -1); Test("TestE1", nullptr, 1, true, -1); printf("\n\n"); } int main(int argc, char* argv[]) { TestA(); TestB(); TestC(); TestD(); TestE(); }
分析:有点困,没太看明白,先占着。
原文:https://www.cnblogs.com/ZSY-blog/p/12655028.html