[试题 基础练习 龟兔赛跑预测]一定要注意细节

import java.io.BufferedWriter;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.util.*;

public class Main {
    static  int v1,v2,t,s,L;
    static String ch;
    public  static  void main(String [] args){
        Scanner sc =new Scanner(System.in);
        int v1 = sc.nextInt();
        int v2 = sc.nextInt();
        int t = sc.nextInt();
        int s = sc.nextInt();
        int L = sc.nextInt();
        int L1=0,L2=0;
        int t1=0,t2=0;
        int x=0;
        while(L1!=L&&L2!=L){
           if(L1-L2>=t){
               t2+=s;
               L2=v2*t2;

           }else{
               t1++;
               t2++;
               L1=v1*t1;
               L2=v2*t2;
           }
        }
       if(L1==L2) {
           System.out.println("D"+"\n"+t2);
       }else if(L1>L2){
           System.out.println("R"+"\n"+t2);
       }else{
           System.out.println("T"+"\n"+L/v2);///这样表示，不能用t2，原因可能是一种情况在兔子休息的时间内（<s）就完成了
       }
   }
}