时间复杂度:\(O(n)\)
class Solution {
public:
int maxProfit(vector<int>& prices) {
int ans = 0;
for (int i = 1; i < prices.size(); ++i) {
if (prices[i] > prices[i - 1]) ans += prices[i] - prices[i - 1];
}
return ans;
}
};
leetcode-----122. 买卖股票的最佳时机 II
原文:https://www.cnblogs.com/clown9804/p/12551994.html