算法训练 拦截导弹（最长递增子序列和最长递减子序列问题，输入回车时停止输入）

 1 #include<iostream>
 2 #include<vector>
 3 using namespace std;
 4 //author:zq
 5 //最长递增子序列 
 6 int addLong(vector<int>obj){
 7     vector<int>result;
 8     result.push_back(obj[0]);
 9     vector<int>::iterator it;
10     for(it=obj.begin()+1;it!=obj.end();it++){
11         if(*it>result[result.size()-1]){
12             result.push_back(*it);
13         }else{
14             for(int i=0;i<result.size();i++){
15                 if(*it<result[i]){
16                     result[i]=*it;
17                     break;
18                 }
19             }
20         }
21     }
22     return result.size();
23 }
24     
25 //最长递减子序列 
26 int minLong(vector<int>obj){
27     vector<int>result;
28     result.push_back(obj[0]);
29     vector<int>::iterator it;
30     for(it=obj.begin()+1;it!=obj.end();it++){
31         if(*it<result[result.size()-1]){
32             result.push_back(*it);
33         }else{
34             for(int i=0;i<result.size();i++){
35                 if(*it>result[i]){
36                     result[i]=*it;
37                     break;
38                 }
39             }
40         }
41     }
42     return result.size();
43 }
44 //    cout<<result.size();
45 int main(){
46     vector<int>objs;
47     int p;
48     char s;
49     while(s!=‘\n‘){
50         cin>>p;
51         s=getchar();
52         objs.push_back(p);
53     }
54     int max,min;
55     max=addLong(objs);
56     min=minLong(objs);
57     cout<<min<<endl<<max;
58     return 0;
59 }