首页 > 其他 > 详细

55. Jump Game

时间:2020-02-17 22:17:29      阅读:56      评论:0      收藏:0      [点我收藏+]

Given an array of non-negative integers, you are initially positioned at the first index of the array.

Each element in the array represents your maximum jump length at that position.

Determine if you are able to reach the last index.

Example 1:

Input: [2,3,1,1,4]
Output: true
Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index.

Example 2:

Input: [3,2,1,0,4]
Output: false
Explanation: You will always arrive at index 3 no matter what. Its maximum
             jump length is 0, which makes it impossible to reach the last index.

 1 class Solution {
 2     public boolean canJump(int[] nums) {
 3         int n = nums.length;
 4         if (n == 0) return false;
 5         
 6         
 7         boolean []dp = new boolean[n + 1];
 8         dp[0] = true;
 9         int now = 0;
10         for (int i = 0; i < n; ++i) {
11             if (i <= now) dp[i] = true;
12             if (dp[i]) {
13                 now = Math.max(now, i + nums[i]);
14             } 
15         }
16         
17         return dp[n - 1];
18     }
19 }

 

55. Jump Game

原文:https://www.cnblogs.com/hyxsolitude/p/12323898.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!