【Python】七段数码管绘制问题

import turtle #引入绘图库turtle
def drawLine(draw):   #绘制单段数码管
    turtle.pendown() if draw else turtle.penup()
    turtle.fd(40) #前进40像素
    turtle.right(90)#旋转90度，完成一条线的绘制
def drawDight(dight):#根据数字绘制七段数码管
    drawLine(True) if dight in [2,3,4,5,6,8,9] else drawLine(False)
    drawLine(True) if dight in [0,1,3,4,5,6,7,8,9] else drawLine(False)
    drawLine(True) if dight in [0,2,3,5,6,8,9] else drawLine(False)
    drawLine(True) if dight in [0,2,6,8] else drawLine(False)
    turtle.left(90)
    drawLine(True) if dight in [0,4,5,6,8,9] else drawLine(False)
    drawLine(True) if dight in [0,2,3,5,6,7,8,9] else drawLine(False)
    drawLine(True) if dight in [0,1,2,3,4,7,8,9] else drawLine(False)
    turtle.left(180)
    turtle.penup() #为绘制后续数字确定位置
    turtle.fd(20) #为绘制后续数字确定位置
def drawDate (date):#获得要输出的数字
    for i in date:
        drawDight(eval(i))  #通过eval()函数家将数字转化为整数
        
def main():
    turtle.setup(800,350,200,200)
    turtle.penup()
    turtle.fd(-300)
    turtle.pensize(5)
    drawDate(‘20200217‘)
    turtle.hideturtle()
    turtle.done()
main()

import turtle #引入绘图库turtle
def drawGap():#绘制数码管间隔,实现数码管效果
    turtle.penup()
    turtle.fd(5)
def drawLine(draw):   #绘制单段数码管
    drawGap()
    turtle.pendown() if draw else turtle.penup()
    turtle.fd(40) #前进40像素
    drawGap()
    turtle.right(90)#旋转90度，完成一条线的绘制
def drawDight(dight):#根据数字绘制七段数码管
    drawLine(True) if dight in [2,3,4,5,6,8,9] else drawLine(False)
    drawLine(True) if dight in [0,1,3,4,5,6,7,8,9] else drawLine(False)
    drawLine(True) if dight in [0,2,3,5,6,8,9] else drawLine(False)
    drawLine(True) if dight in [0,2,6,8] else drawLine(False)
    turtle.left(90)
    drawLine(True) if dight in [0,4,5,6,8,9] else drawLine(False)
    drawLine(True) if dight in [0,2,3,5,6,7,8,9] else drawLine(False)
    drawLine(True) if dight in [0,1,2,3,4,7,8,9] else drawLine(False)
    turtle.left(180)
    turtle.penup() #为绘制后续数字确定位置
    turtle.fd(20) #为绘制后续数字确定位置
def drawDate (date):#获得要输出的数字
    for i in date:
        drawDight(eval(i))  #通过eval()函数家将数字转化为整数
        
def main():
    turtle.setup(800,350,200,200)
    turtle.penup()
    turtle.fd(-300)
    turtle.pensize(5)
    drawDate(‘20200217‘)
    turtle.hideturtle()
    turtle.done()
main()

import turtle,time #引入绘图库turtle time库
def drawGap():#绘制数码管间隔,实现数码管效果
    turtle.penup()
    turtle.fd(5)
def drawLine(draw):   #绘制单段数码管
    drawGap()
    turtle.pendown() if draw else turtle.penup()
    turtle.fd(40) #前进40像素
    drawGap()
    turtle.right(90)#旋转90度，完成一条线的绘制
def drawDight(dight):#根据数字绘制七段数码管
    drawLine(True) if dight in [2,3,4,5,6,8,9] else drawLine(False)
    drawLine(True) if dight in [0,1,3,4,5,6,7,8,9] else drawLine(False)
    drawLine(True) if dight in [0,2,3,5,6,8,9] else drawLine(False)
    drawLine(True) if dight in [0,2,6,8] else drawLine(False)
    turtle.left(90)
    drawLine(True) if dight in [0,4,5,6,8,9] else drawLine(False)
    drawLine(True) if dight in [0,2,3,5,6,7,8,9] else drawLine(False)
    drawLine(True) if dight in [0,1,2,3,4,7,8,9] else drawLine(False)
    turtle.left(180)
    turtle.penup() #为绘制后续数字确定位置
    turtle.fd(20) #为绘制后续数字确定位置
def drawDate (date):#data为日期，格式为“%Y-%m=%d+”
    turtle.pencolor("red")
    for i in date:
       if i==‘-‘:
           turtle.write(‘年‘,font=("Arial",18,"normal"))
           turtle.pencolor("green")
           turtle.fd(40)
       elif i==‘=‘:
           turtle.write(‘月‘,font=("Arial",18,"normal"))
           turtle.pencolor("blue")
           turtle.fd(40)
       elif i==‘+‘:
           turtle.write(‘日‘,font=("Arial",18,"normal"))
       else:
           drawDight(eval(i))

def main():
    turtle.setup(800,350,200,200)
    turtle.penup()
    turtle.fd(-300)
    turtle.pensize(5)
    drawDate(time.strftime(‘%Y-%m=%d+‘,time.gmtime()))#获取系统时间并格式化
    turtle.hideturtle()
    turtle.done()
main()