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Python装饰器限制函数运行时间超时则退出执行 函数超时停止

时间:2020-01-10 15:03:23      阅读:300      评论:0      收藏:0      [点我收藏+]

https://www.jb51.net/article/159375.htm


# -*- coding: utf-8 -*-
from threading import Thread
import time
class TimeoutException(Exception):
  pass
ThreadStop = Thread._Thread__stop
def timelimited(timeout):
  def decorator(function):
    def decorator2(*args,**kwargs):
      class TimeLimited(Thread):
        def __init__(self,_error= None,):
          Thread.__init__(self)
          self._error = _error
        def run(self):
          try:
            self.result = function(*args,**kwargs)
          except Exception,e:
            self._error = str(e)
        def _stop(self):
          if self.isAlive():
            ThreadStop(self)
      t = TimeLimited()
      t.start()
      t.join(timeout)
      if isinstance(t._error,TimeoutException):
        t._stop()
        raise TimeoutException(timeout for %s % (repr(function)))
      if t.isAlive():
        t._stop()
        raise TimeoutException(timeout for %s % (repr(function)))
      if t._error is None:
        return t.result
    return decorator2
  return decorator
@timelimited(2) # 设置运行超时时间2S
def fn_1(secs):
  time.sleep(secs)
  return Finished without timeout
def do_something_after_timeout():
  print(Time out!)
if __name__ == "__main__":
  try:
    print(fn_1(3)) # 设置函数执行3S
  except TimeoutException as e:
    print(str(e))
    do_something_after_timeout()

Python装饰器限制函数运行时间超时则退出执行 函数超时停止

原文:https://www.cnblogs.com/angdh/p/12175796.html

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