1日期问题
题解如下：
#include<stdio.h> #include<math.h> int year [2][13]= { {0,31,28,31,30,31,30,31,31,30,31,30,31}, {0,31,29,31,30,31,30,31,31,30,31,30,31}, }; bool isLeap(int year)//判断是否是闰年 { return ((year%4==0 && year%100!=0)||(year%400==0)) ; } int main() { int t1,y1,m1,d1; int t2,y2,m2,d2; while(scanf("%d%d",&t1,&t2)!=EOF){ if(t1>t2) { int n=t1; t1=t2; t2=n; } y1=t1/10000,m1=t1%10000/100, d1=t1%10; y2=t2/10000,m2=t2%10000/100, d2=t2%10; int ans=1; while(!(y1==y2&&m1==m2&&d1==d2)) { d1++; ans++; if(d1==year[isLeap(y1)][m1]+1 ) //满当月天数 { m1++; d1=1; } if(m1>12) { y1++; m1=1; } } printf("%d",ans); } return 0; }
2. 进制问题
#include<stdio.h> //p进制数x转化为十进制y int main() { int p,x; scanf("%d%d",&p,&x); int y=0,product =1; while(x!=0){ y=y+(x%10)*product; x=x/10; product*=p; } printf("%d",y); return 0; }
#include<stdio.h> //10进制数y转化为Q进制z int main() { int z[40],num=0; int y,q; scanf("%d%d",&y,&q); do{ z[num++]=y%q; y=y/q; }while(y!=0); for(int i=num-1;i--;i>0) { printf("%d",z[i]); } return 0; }
3字符串问题
题解如下：
#include<stdio.h> #include<math.h> #include<cstring> int main() { char str[90][90]; int i=0; while(scanf("%s",str[i])!=EOF) { i++; } for(i=i-1;i>=0;i--) { printf("%s",str[i]); if(i>0) printf(" "); } return 0; }
原文：https://www.cnblogs.com/wml2018/p/12156730.html