Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 37448 Accepted Submission(s): 15826
import java.util.Scanner;
public class Main {
static int[][] map;
static int k, n, m, res;
static int[] a;
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
while (input.hasNext()) {
res = 0;
k = input.nextInt();
if(k ==0)
break;
n = input.nextInt();
m = input.nextInt();
a = new int[m + 1];
map = new int[n + 1][m + 1];
for (int i = 0; i < k; i++) {
int x, y;
x = input.nextInt();
y = input.nextInt();
map[x][y] = 1;
}
dfs(1, 0);
System.out.println(res);
}
}
public static void dfs(int index, int count){
if(index>n){
if(count>res){
res = count;
}
return;
}
for (int i=1; i<=m; i++){
if(map[index][i]==1 && a[i]==0){
a[i] = 1;
dfs(index+1, count+1);
a[i] =0;
}
}
dfs(index+1, count);
}
}
import java.util.Arrays;
import java.util.Scanner;
public class Main {
static int[][] map = new int[501][501];//用来存女生是否中意男生
static int k, n, m;
static int[] a = new int[501], b = new int[501];//a数组用来标记选取状况0-1,b数组存的是选中这个男生的女生编号
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
while (input.hasNext()) {
k = input.nextInt();
if(k ==0)
break;
n = input.nextInt();
m = input.nextInt();
//初始化操作,因为有多组数据,所以每次循环要初始化为0
Arrays.fill(b, 0);
for (int i=0; i<=n; i++){
Arrays.fill(map[i], 0);
}
int x, y;
for (int i = 0; i < k; i++) {
x = input.nextInt();
y = input.nextInt();
map[x][y] = 1;
}
int res=0;
for(int i=1; i<=n; i++){//遍历每个女生
Arrays.fill(a, 0);
if(dfs(i))//查看女生是否能找到伴,是就res+1
res++;
}
System.out.println(res);//最后输出结果
}
}
public static boolean dfs(int index){
for (int i=1; i<=m; i++){//遍历每个男生
if(map[index][i]==1 && a[i]==0){//中意,并且没有被标记
a[i]=1;//先将男生i标记为选中
if(b[i]==0 || dfs(b[i])){//假如b[i]==0就是说男生还没有被选, 就会直接执行下面的,如果b[i]不等于0,dfs(b[i])就让选中该男生的女生换一个选。
b[i] = index;//标记第i个男生的女伴为index
return true;
}
}
}
return false;
}
}
原文:https://www.cnblogs.com/qiulonghai/p/12103988.html