Given an input string, reverse the string word by word.
For example,
Given s = "the sky is blue",
return "blue is sky the".
class Solution {
public:
void reverseWords(string &s) {
int begin = 0;
int end = 0;
while(end < s.size()){
if(s[end] == ' '){
swapString(s, begin, end - 1);
begin = end+1;
end = begin;
}
else{
end++;
}
}
swapString(s, begin, end - 1);
swapString(s, 0, s.size()-1);
}
void swapString(string &s, int begin, int end){
while(end > begin){
char c = s[begin];
s[begin] = s[end];
s[end] = c;
begin++;
end--;
}
}
};class Solution {
public:
void reverseWords(string &s) {
stack<int> word;
stack<int> sentence;
int i = 0;
while(i <= s.size()){
if(i == s.size() || s[i] == ' '){
if(!word.empty()){
if(!sentence.empty()){
sentence.push(' ');
}
while(!word.empty()){
sentence.push(word.top());
word.pop();
}
}
} else{
word.push(s[i]);
}
i++;
};
s.clear();
while(!sentence.empty()){
s.push_back(sentence.top());
sentence.pop();
};
}
};LeetCode | Reverse Words in a String
原文:http://blog.csdn.net/lanxu_yy/article/details/38827845