sizeof与strlen

#include <stdio.h>
#include <string.h>
#include<stdlib.h>
void testArr(const char str[])
{
printf("%lu %lu\n", sizeof(str), strlen(str));
}
int main(void)
{

char str[] = "hello";
printf("test0 %lu %lu\n\n", sizeof(str), strlen(str));

char str1[8] = "hello";
printf("test1 %lu %lu\n\n", sizeof(str1), strlen(str1));

char str2[] = { ‘h‘,‘e‘,‘l‘,‘l‘,‘o‘ };
printf("test2 %lu %lu\n\n", sizeof(str2), strlen(str2));

char *str3 = "hello";
printf("test3 %lu %lu\n\n", sizeof(str3), strlen(str3));

char str4[] = "hello";
testArr(str4);

char str5[] = "hell\0o";
printf("test5 %lu %lu\n", sizeof(str5), strlen(str5));

char str6[10] = { 0 };
printf("test6 %lu %lu\n\n", sizeof(str6), strlen(str6));

char str8[5] = { 0 };
strncpy(str8, "hello", 5);
printf("%s\n", str8);
system("pause");
return 0;
}

sizeof与strlen

原文：https://www.cnblogs.com/tiange-137/p/11919599.html