使用Python的栈实现括号匹配算法

写一个栈的类：stack.py

class Stack:
    def __init__(self):
        self.items = []

    def is_Empty(self):
        return self.items == []

    def push(self, item):
        self.items.append(item)

    def pop(self):
        return self.items.pop()

    def peek(self):
        return self.items[len(items)-1]
    def size(self):
        return len(self.items)

实现括号匹配的算法程序：

from stack import Stack
def parChecker(symbolString):
    s = Stack()
    balanced = True
    index = 0
    while index < len(symbolString) and balanced:
        symbol = symbolString[index]
        if symbol == "(":
            s.push(symbol)
        elif symbol == ")":
            if s.is_Empty():
                balanced = False
            else:
                s.pop()

        index += 1
    if balanced and s.is_Empty():
        return True
    else:
        return False

print(parChecker("(((2356)))"))

输出结果：
True
再测试

print(parChecker("(()))"))

输出结果False

扩展

能够匹配多种括号，{},[]
只需要小小的改动代码：

from stack import Stack

def parChecker(symbolString):
    s = Stack()
    balanced = True
    index = 0
    while index < len(symbolString) and balanced:
        symbol = symbolString[index]
        if symbol in "({[":
            s.push(symbol)
        elif symbol in ")}]":
            if s.is_Empty():
                balanced = False
            else:
                s.pop()

        index += 1
    if balanced and s.is_Empty():
        return True
    else:
        return False

print(parChecker("[(({fdf}))]"))

使用Python的栈实现括号匹配算法

原文：https://blog.51cto.com/13560219/2447832