223. Rectangle Area

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Example:

Input: A = -3, B = 0, C = 3, D = 4, E = 0, F = -1, G = 9, H = 2
Output: 45

Note:

Assume that the total area is never beyond the maximum possible value of int.

class Solution {
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int area = (C - A) * (D - B) + (G - E) * (H - F);  
        if(C < E || G < A || D < F || B > H) return area;
        int overlap = (Math.min(C, G) - Math.max(A, E)) *
                (Math.min(D, H) - Math.max(B, F));
        return area - overlap;
        
    }
}

 相交部分，长由   俩长方形右侧取小值 - 左侧取大值　　得到

                   宽由   俩长方形上侧去小值 - 下侧取大值　　得到。

223. Rectangle Area

原文：https://www.cnblogs.com/wentiliangkaihua/p/11706217.html