题目描述:
方法:二分 O(log(min(m,n)))
class Solution: def findMedianSortedArrays(self, nums1: List[int], nums2: List[int]) -> float: n1 = len(nums1) n2 = len(nums2) if n1 > n2: return self.findMedianSortedArrays(nums2,nums1) k = (n1 + n2 + 1)//2 left = 0 right = n1 while left < right : m1 = left +(right - left)//2 m2 = k - m1 if nums1[m1] < nums2[m2-1]: left = m1 + 1 else: right = m1 m1 = left m2 = k - m1 c1 = max(nums1[m1-1] if m1 > 0 else float("-inf"), nums2[m2-1] if m2 > 0 else float("-inf") ) if (n1 + n2) % 2 == 1: return c1 c2 = min(nums1[m1] if m1 < n1 else float("inf"), nums2[m2] if m2 <n2 else float("inf")) return (c1 + c2) / 2
原文:https://www.cnblogs.com/oldby/p/11644031.html