https://codeforces.com/contest/1234/problem/D
写了个巨蠢的线段树(不愧是垃圾),有必要提醒下自己这种题怎么做
#include<iostream>
#include<cstdio>
#include<string>
#include<set>
#include<algorithm>
using namespace std;
const int maxn = 32;
set<int> st[maxn];
int main()
{
string words;
cin>>words;
words = ‘.‘ + words;
int len = words.size() - 1;
for(int i=1;i<=len;++i)
st[words[i]-‘a‘].insert(i);
int q,cmd,pos,l,r;
char ch; scanf("%d",&q);
for(int k=0;k!=q;++k)
{
scanf("%d",&cmd);
if(cmd==1)
{
scanf("%d",&pos);
getchar();
scanf("%c",&ch);
st[words[pos]-‘a‘].erase(pos);
words[pos] = ch;
st[words[pos]-‘a‘].insert(pos);
}else{
int ans = 0;
scanf("%d%d",&l,&r);
for(int i=0;i!=26;++i)
{
auto it = st[i].lower_bound(l);//MDZZ 再也不直接用algorithm的二分了,容器内的快多了,佛了
if(it == st[i].end())
continue;//找到大于等于l开始的字符,因为不重复,所以只需要找出一个就好了(ORZ)
int x = *it;
if(x <= r)
++ans;
}
cout<<ans<<‘\n‘;
}
}
}
垃圾如我,哭啦
原文:https://www.cnblogs.com/newstartCY/p/11616651.html