开始想出来了一个容斥的做法,但是一直WA,后来换了一种统计方式就对了.
#include <bits/stdc++.h>
#define mod 1000000007
#define ll unsigned long long
#define setIO(s) freopen(s".in","r",stdin)
using namespace std;
vector<ll>v;
ll qpow(ll base,ll k)
{
ll tmp=1ll;
for(;k;k>>=1,base=base*base%mod) if(k&1) tmp=tmp*base%mod;
return tmp;
}
int main()
{
int i,j;
ll x,n,p;
// setIO("input");
scanf("%lld%lld",&x,&n);
p=x;
for(i=2;i*i<=p;++i)
{
if(p%i==0)
{
v.push_back(i);
for(;p%i==0;) p/=i;
}
}
if(p>1) v.push_back(p);
ll ans=1ll;
for(i=0;i<v.size();++i)
{
ll m=n;
ll now=0;
while(m>=v[i])
{
now+=m/v[i];
m/=v[i];
}
ans=ans*qpow(v[i], now)%mod;
}
printf("%lld\n",(long long)ans);
return 0;
}
CF #589 (Div. 2)C. Primes and Multiplication 快速幂+质因数
原文:https://www.cnblogs.com/guangheli/p/11610963.html