v = "alex"v = v.replace("l","el")print(v)li = [11,22,33,44,55]li[0] = 00print(li)#补充:错误,字符串创建后不可更改li ="alex"li[0]li[0] = "E"
Python 列表魔法三
原文：https://www.cnblogs.com/159357zzx/p/11581178.html
