Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i].
After this process, we have some array B.
Return the smallest possible difference between the maximum value of B and the minimum value of B.
Example 1:
Input: A = [1], K = 0
Output: 0
Explanation: B = [1]
Example 2:
Input: A = [0,10], K = 2
Output: 6
Explanation: B = [2,8]
Example 3:
Input: A = [1,3,6], K = 3
Output: 0
Explanation: B = [3,3,3] or B = [4,4,4]
Note:
1 <= A.length <= 100000 <= A[i] <= 100000 <= K <= 10000
class Solution { public int smallestRangeI(int[] A, int K) { if(A==null||A.length==1){ return 0; } Arrays.sort(A); int second = A[0]; int first = A[A.length -1]; if((first - second)<=2*K){ return 0 ; } else { return first - second - K - K ; } } }
908. Smallest Range I - LeetCode
原文：https://www.cnblogs.com/codingyangmao/p/11571797.html