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Sumdiv POJ - 1845 A^b约数之和取模 内部递归 外部分治

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Consider two natural numbers A and B. Let S be the sum of all natural divisors of A^B. Determine S modulo 9901 (the rest of the division of S by 9901).
Input
The only line contains the two natural numbers A and B, (0 <= A,B <= 50000000)separated by blanks.
Output
The only line of the output will contain S modulo 9901.
Sample Input
2 3
Sample Output
15
Hint
2^3 = 8.
The natural divisors of 8 are: 1,2,4,8. Their sum is 15.
15 modulo 9901 is 15 (that should be output).
 

Sumdiv POJ - 1845 A^b约数之和取模 内部递归 外部分治

原文:https://www.cnblogs.com/LS-Joze/p/11567148.html

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