环境Xcode 11.0 beta4 swift 5.1
示例如下
struct BlackjackCard {
// nested Suit enumeration
enum Suit: Character {
case spades = "?", hearts = "?", diamonds = "?", clubs = "?"
}
//
// nested Rank enumeration
enum Rank: Int {
case two = 2, three, four, five, six, seven, eight, nine, ten
case jack, queen, king, ace
struct Values {
let first: Int, second: Int?
}
var values: Values {
switch self {
case .ace:
return Values(first: 1, second: 11)
case .jack, .queen, .king:
return Values(first: 10, second: nil)
default:
return Values(first: self.rawValue, second: nil)
}
}
}
//
// BlackjackCard properties and methods
let rank: Rank, suit: Suit
var description: String {
var output = "suit is \(suit.rawValue),"
output += " value is \(rank.values.first)"
if let second = rank.values.second {
output += " or \(second)"
}
return output
}
}
// BlackjackCard 内嵌套了两个枚举类型 Rank、Suit,Rank有一个更深的嵌套类型Values
// BlackjackCard 有两个存储属性,没有显示的构造器, 由于Rank、Suit 都是其嵌套类型,所以可以推导出类型,下面可以直接(
.ace .spades)
let theAceOfSpades = BlackjackCard(rank: .ace, suit: .spades)
print("theAceOfSpades: \(theAceOfSpades.description)")
// Prints "theAceOfSpades: suit is ?, value is 1 or 11"
示例
let heartSymbol = BlackjackCard.Suit.hearts.rawValue
// heartSymbol is "?"
原文:https://www.cnblogs.com/tzsh1007/p/11557005.html